Electricity: Difference between revisions
GT power loss was changed and not fixed here for the most part
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(GT power loss was changed and not fixed here for the most part) |
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!LV
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!MV
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!HV
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!EV
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!IV
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!LuV
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!ZPMV
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Let's first define our terms, a segment is the length of a Battery plus a number of sequential Cables.
The efficiency of such a segment will be <math>\frac{8\times4^T-(D-1)\times L}{8\times4^T+2^{T-1}}</math>.
T is the tier (
L is the loss of the cable in voltage/meter/ampere.
D is the distance of the segment, so the length of the Cables plus the battery.
<!--T:114-->
But this is no good since we want to figure out the optimal length when there is an element of exponential decline that we haven't accounted for. We do this by making an expression of how much efficiency we get in each single block if there was a uniform exponential decline over the whole segment. This turns out to be <math>\left(\frac{8\times4^T-(D-1)\times L}{8\times4^T+2^{T-1}}\right)^\frac{1}{D}</math>.
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Step 1: go to http://www.wolframalpha.com/ because we are lazy. Step 2: Enter "(d/dD) ((8 * 4^T - (D - 1)L) / (8 * 4^T + 2^(T - 1)))^(1 / D) = 0, T=<Insert tier here>, L=<Insert Cable loss here>". It will solve the problem numerically for each separate case. So if you want to know the optimal length of Annealed Copper Cable between your MV Batteries, you enter T=2, L=1 and it will give you the optimal length of each segment (This includes the battery!). In the case of Annealed Copper Cable this turns out to be about
== Transformers ==
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